What are the solutions to the equation 600-200x+12x^2=0 ?

The solutions to the equation 600-200x+12x^2=0 are x=(5(5+sqrt(7)))/3 ,x=(5(5-sqrt(7)))/3

Find the zeros of 600-200x+12x^2=0

The zeros of 600-200x+12x^2=0 are x=(5(5+sqrt(7)))/3 ,x=(5(5-sqrt(7)))/3

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600 - 200 x + 12 x^{2} = 0

x = \frac{5 ( 5 + 7 )}{3}, x = \frac{5 ( 5 - 7 )}{3}

Decimal Notation

x = 12.74291 \dots, x = 3.92374 \dots

Solution steps

600 - 200 x + 12 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} - 200 x + 600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 200 ) \pm ( - 200 ) ^{2} - 4 \cdot 12 \cdot 600}{2 \cdot 12}

(- 200)^{2} - 4 \cdot 12 \cdot 600 = 407

x_{1, 2} = \frac{- ( - 200 ) \pm 40 7}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 200 ) + 40 7}{2 \cdot 12}, x_{2} = \frac{- ( - 200 ) - 40 7}{2 \cdot 12}

x = \frac{- ( - 200 ) + 40 7}{2 \cdot 12} : \frac{5 ( 5 + 7 )}{3}

x = \frac{- ( - 200 ) - 40 7}{2 \cdot 12} : \frac{5 ( 5 - 7 )}{3}

The solutions to the quadratic equation are:

x = \frac{5 ( 5 + 7 )}{3}, x = \frac{5 ( 5 - 7 )}{3}

x, x^{2} - 2 x + 184 = 2 x

- x^{2} + 7 x = - 1

2 x^{2} - 6 x + 15 = 0

(x - 2)^{2} + x (x + 1) = 24

x, x^{2} + k x + k = x - 2

What are the solutions to the equation 600-200x+12x^2=0 ?
The solutions to the equation 600-200x+12x^2=0 are x=(5(5+sqrt(7)))/3 ,x=(5(5-sqrt(7)))/3
Find the zeros of 600-200x+12x^2=0
The zeros of 600-200x+12x^2=0 are x=(5(5+sqrt(7)))/3 ,x=(5(5-sqrt(7)))/3