What are the solutions to the equation 17x^2+119x+102=0 ?

The solutions to the equation 17x^2+119x+102=0 are x=-1,x=-6

Find the zeros of 17x^2+119x+102=0

The zeros of 17x^2+119x+102=0 are x=-1,x=-6

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17 x^{2} + 119 x + 102 = 0

x = - 1, x = - 6

Solution steps

17 x^{2} + 119 x + 102 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 119 \pm 11 9 ^{2} - 4 \cdot 17 \cdot 102}{2 \cdot 17}

11 9^{2} - 4 \cdot 17 \cdot 102 = 85

x_{1, 2} = \frac{- 119 \pm 85}{2 \cdot 17}

Separate the solutions

x_{1} = \frac{- 119 + 85}{2 \cdot 17}, x_{2} = \frac{- 119 - 85}{2 \cdot 17}

x = \frac{- 119 + 85}{2 \cdot 17} : - 1

x = \frac{- 119 - 85}{2 \cdot 17} : - 6

The solutions to the quadratic equation are:

x = - 1, x = - 6

2 y^{2} - 72 = 0

2 n^{2} + 4 n - 6 = 0

7 x^{2} - 4 x = - 1

x, 9 x^{2} - 6 x y + y^{2} - 12 x + 4 y + 4 = 0

x, x^{2} ln (y) + e^{y^{2}} = 25 + y

What are the solutions to the equation 17x^2+119x+102=0 ?
The solutions to the equation 17x^2+119x+102=0 are x=-1,x=-6
Find the zeros of 17x^2+119x+102=0
The zeros of 17x^2+119x+102=0 are x=-1,x=-6