What are the solutions to the equation 20x^2+11x-3=0 ?

The solutions to the equation 20x^2+11x-3=0 are x= 1/5 ,x=-3/4

Find the zeros of 20x^2+11x-3=0

The zeros of 20x^2+11x-3=0 are x= 1/5 ,x=-3/4

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20 x^{2} + 11 x - 3 = 0

x = \frac{1}{5}, x = - \frac{3}{4}

Decimal Notation

x = 0.2, x = - 0.75

Solution steps

20 x^{2} + 11 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 20 ( - 3 )}{2 \cdot 20}

1 1^{2} - 4 \cdot 20 (- 3) = 19

x_{1, 2} = \frac{- 11 \pm 19}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- 11 + 19}{2 \cdot 20}, x_{2} = \frac{- 11 - 19}{2 \cdot 20}

x = \frac{- 11 + 19}{2 \cdot 20} : \frac{1}{5}

x = \frac{- 11 - 19}{2 \cdot 20} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = - \frac{3}{4}

209 - 120 x + 12 x^{2} = 0

x, x^{2} + y^{2} + 2 x + 1 = 0

x, 2 x^{2} - 4 x - 1 = 0

\frac{x ^{2} + 10}{2} = 19

x^{2} - 10 x - 4

What are the solutions to the equation 20x^2+11x-3=0 ?
The solutions to the equation 20x^2+11x-3=0 are x= 1/5 ,x=-3/4
Find the zeros of 20x^2+11x-3=0
The zeros of 20x^2+11x-3=0 are x= 1/5 ,x=-3/4