What are the solutions to the equation solvefor x,x^2+kx+4=0 ?

The solutions to the equation solvefor x,x^2+kx+4=0 are x=(-k+sqrt(k^2-16))/2 ,x=(-k-sqrt(k^2-16))/2

Find the zeros of solvefor x,x^2+kx+4=0

The zeros of solvefor x,x^2+kx+4=0 are x=(-k+sqrt(k^2-16))/2 ,x=(-k-sqrt(k^2-16))/2

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x, x^{2} + k x + 4 = 0

x = \frac{- k + k ^{2} - 16}{2}, x = \frac{- k - k ^{2} - 16}{2}

Solution steps

x^{2} + k x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- k \pm k ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

k^{2} - 4 \cdot 1 \cdot 4 : k^{2} - 16

x_{1, 2} = \frac{- k \pm k ^{2} - 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- k + k ^{2} - 16}{2 \cdot 1}, x_{2} = \frac{- k - k ^{2} - 16}{2 \cdot 1}

x = \frac{- k + k ^{2} - 16}{2 \cdot 1} : \frac{- k + k ^{2} - 16}{2}

x = \frac{- k - k ^{2} - 16}{2 \cdot 1} : \frac{- k - k ^{2} - 16}{2}

The solutions to the quadratic equation are:

x = \frac{- k + k ^{2} - 16}{2}, x = \frac{- k - k ^{2} - 16}{2}

x^{2} + 8 x + 14 = 23

0 = - (x - 5)^{2} + 9

x^{2} - 2 x - 6

x^{2} - 2 x + 4

x^{2} - 3 x = 2 (x + 7)

What are the solutions to the equation solvefor x,x^2+kx+4=0 ?
The solutions to the equation solvefor x,x^2+kx+4=0 are x=(-k+sqrt(k^2-16))/2 ,x=(-k-sqrt(k^2-16))/2
Find the zeros of solvefor x,x^2+kx+4=0
The zeros of solvefor x,x^2+kx+4=0 are x=(-k+sqrt(k^2-16))/2 ,x=(-k-sqrt(k^2-16))/2