What are the solutions to the equation x^2-10x+39=0 ?

The solutions to the equation x^2-10x+39=0 are x=5+sqrt(14)i,x=5-sqrt(14)i

Find the zeros of x^2-10x+39=0

The zeros of x^2-10x+39=0 are x=5+sqrt(14)i,x=5-sqrt(14)i

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x^{2} - 10 x + 39 = 0

x = 5 + 14 i, x = 5 - 14 i

Solution steps

x^{2} - 10 x + 39 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 39}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot 39 : 214 i

x_{1, 2} = \frac{- ( - 10 ) \pm 2 14 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 14 i}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 14 i}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 14 i}{2 \cdot 1} : 5 + 14 i

x = \frac{- ( - 10 ) - 2 14 i}{2 \cdot 1} : 5 - 14 i

The solutions to the quadratic equation are:

x = 5 + 14 i, x = 5 - 14 i

2 x^{2} + 9 x + 20 = 0

- 4 r^{2} - 4 r - 8 = - 7

3 x^{2} - 7 x - 40 = 0

3 x^{2} + x = 10

2 x^{2} + 4 x - 16 = 0

What are the solutions to the equation x^2-10x+39=0 ?
The solutions to the equation x^2-10x+39=0 are x=5+sqrt(14)i,x=5-sqrt(14)i
Find the zeros of x^2-10x+39=0
The zeros of x^2-10x+39=0 are x=5+sqrt(14)i,x=5-sqrt(14)i