What are the solutions to the equation (5x-3)^2-11(4x+1)=1 ?

The solutions to the equation (5x-3)^2-11(4x+1)=1 are x=3,x=-1/25

Find the zeros of (5x-3)^2-11(4x+1)=1

The zeros of (5x-3)^2-11(4x+1)=1 are x=3,x=-1/25

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(5 x - 3)^{2} - 11 (4 x + 1) = 1

x = 3, x = - \frac{1}{25}

Decimal Notation

x = 3, x = - 0.04

Solution steps

(5 x - 3)^{2} - 11 (4 x + 1) = 1

Expand

(5 x - 3)^{2} - 11 (4 x + 1) : 25 x^{2} - 74 x - 2

25 x^{2} - 74 x - 2 = 1

Move

1

to the left side

25 x^{2} - 74 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 74 ) \pm ( - 74 ) ^{2} - 4 \cdot 25 ( - 3 )}{2 \cdot 25}

(- 74)^{2} - 4 \cdot 25 (- 3) = 76

x_{1, 2} = \frac{- ( - 74 ) \pm 76}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 74 ) + 76}{2 \cdot 25}, x_{2} = \frac{- ( - 74 ) - 76}{2 \cdot 25}

x = \frac{- ( - 74 ) + 76}{2 \cdot 25} : 3

x = \frac{- ( - 74 ) - 76}{2 \cdot 25} : - \frac{1}{25}

The solutions to the quadratic equation are:

x = 3, x = - \frac{1}{25}

y^{2} + 3 y - 1 = 0

z^{2} - 3 z = 54

s^{2} + 10 s + 61

3 x^{2} - 8 x + 4 = 0

3 x^{2} + 7 x = 9

What are the solutions to the equation (5x-3)^2-11(4x+1)=1 ?
The solutions to the equation (5x-3)^2-11(4x+1)=1 are x=3,x=-1/25
Find the zeros of (5x-3)^2-11(4x+1)=1
The zeros of (5x-3)^2-11(4x+1)=1 are x=3,x=-1/25