What are the solutions to the equation x^2+18x-4=0 ?

The solutions to the equation x^2+18x-4=0 are x=-9+sqrt(85),x=-9-sqrt(85)

Find the zeros of x^2+18x-4=0

The zeros of x^2+18x-4=0 are x=-9+sqrt(85),x=-9-sqrt(85)

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x^{2} + 18 x - 4 = 0

x = - 9 + 85, x = - 9 - 85

Decimal Notation

x = 0.21954 \dots, x = - 18.21954 \dots

Solution steps

x^{2} + 18 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot (- 4) = 285

x_{1, 2} = \frac{- 18 \pm 2 85}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 2 85}{2 \cdot 1}, x_{2} = \frac{- 18 - 2 85}{2 \cdot 1}

x = \frac{- 18 + 2 85}{2 \cdot 1} : - 9 + 85

x = \frac{- 18 - 2 85}{2 \cdot 1} : - 9 - 85

The solutions to the quadratic equation are:

x = - 9 + 85, x = - 9 - 85

a (x + b) - (x + a)^{2} = x^{2}

x^{2} - 16 x = - 55

6 x^{2} + 5 x = 4

25 r^{2} + 3 = 4

4 x^{2} - 169 = 0

What are the solutions to the equation x^2+18x-4=0 ?
The solutions to the equation x^2+18x-4=0 are x=-9+sqrt(85),x=-9-sqrt(85)
Find the zeros of x^2+18x-4=0
The zeros of x^2+18x-4=0 are x=-9+sqrt(85),x=-9-sqrt(85)