What are the solutions to the equation x^2+7x-98=0 ?

The solutions to the equation x^2+7x-98=0 are x=7,x=-14

Find the zeros of x^2+7x-98=0

The zeros of x^2+7x-98=0 are x=7,x=-14

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x^{2} + 7 x - 98 = 0

x = 7, x = - 14

Solution steps

x^{2} + 7 x - 98 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 98 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 98) = 21

x_{1, 2} = \frac{- 7 \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 21}{2 \cdot 1}, x_{2} = \frac{- 7 - 21}{2 \cdot 1}

x = \frac{- 7 + 21}{2 \cdot 1} : 7

x = \frac{- 7 - 21}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

x = 7, x = - 14

x^{2} + 18 x - 4 = 0

a (x + b) - (x + a)^{2} = x^{2}

x^{2} - 16 x = - 55

6 x^{2} + 5 x = 4

25 r^{2} + 3 = 4

What are the solutions to the equation x^2+7x-98=0 ?
The solutions to the equation x^2+7x-98=0 are x=7,x=-14
Find the zeros of x^2+7x-98=0
The zeros of x^2+7x-98=0 are x=7,x=-14