What are the solutions to the equation factor 6x^2+5x=4 ?

The solutions to the equation factor 6x^2+5x=4 are x= 1/2 ,x=-4/3

Find the zeros of factor 6x^2+5x=4

The zeros of factor 6x^2+5x=4 are x= 1/2 ,x=-4/3

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6 x^{2} + 5 x = 4

x = \frac{1}{2}, x = - \frac{4}{3}

Solution steps

6 x^{2} + 5 x = 4

Move

4

to the left side

6 x^{2} + 5 x - 4 = 0

Factor

6 x^{2} + 5 x - 4 : (2 x - 1) (3 x + 4)

(2 x - 1) (3 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or 3 x + 4 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

3 x + 4 = 0 : x = - \frac{4}{3}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{4}{3}

25 r^{2} + 3 = 4

4 x^{2} - 169 = 0

a^{2} + 2 a - 5 = 0

3 x = \frac{1}{5} x^{2} + 10

x^{2} - 18 x - 360 = 0

What are the solutions to the equation factor 6x^2+5x=4 ?
The solutions to the equation factor 6x^2+5x=4 are x= 1/2 ,x=-4/3
Find the zeros of factor 6x^2+5x=4
The zeros of factor 6x^2+5x=4 are x= 1/2 ,x=-4/3