What are the solutions to the equation 4x^2-169=0 ?

The solutions to the equation 4x^2-169=0 are x= 13/2 ,x=-13/2

Find the zeros of 4x^2-169=0

The zeros of 4x^2-169=0 are x= 13/2 ,x=-13/2

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4 x^{2} - 169 = 0

x = \frac{13}{2}, x = - \frac{13}{2}

Solution steps

4 x^{2} - 169 = 0

Move

169

to the right side

4 x^{2} = 169

Divide both sides by

4

x^{2} = \frac{169}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{169}{4}, x = - \frac{169}{4}

\frac{169}{4} = \frac{13}{2}

- \frac{169}{4} = - \frac{13}{2}

x = \frac{13}{2}, x = - \frac{13}{2}

a^{2} + 2 a - 5 = 0

3 x = \frac{1}{5} x^{2} + 10

x^{2} - 18 x - 360 = 0

w, x yz + x z w - yz w + w^{2} = 5

4 x^{2} + 12 x - 3 = 0

What are the solutions to the equation 4x^2-169=0 ?
The solutions to the equation 4x^2-169=0 are x= 13/2 ,x=-13/2
Find the zeros of 4x^2-169=0
The zeros of 4x^2-169=0 are x= 13/2 ,x=-13/2