What are the solutions to the equation 4x^2+12x-3=0 ?

The solutions to the equation 4x^2+12x-3=0 are x=(-3+2sqrt(3))/2 ,x=-(3+2sqrt(3))/2

Find the zeros of 4x^2+12x-3=0

The zeros of 4x^2+12x-3=0 are x=(-3+2sqrt(3))/2 ,x=-(3+2sqrt(3))/2

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4 x^{2} + 12 x - 3 = 0

x = \frac{- 3 + 2 3}{2}, x = - \frac{3 + 2 3}{2}

Decimal Notation

x = 0.23205 \dots, x = - 3.23205 \dots

Solution steps

4 x^{2} + 12 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 (- 3) = 83

x_{1, 2} = \frac{- 12 \pm 8 3}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 8 3}{2 \cdot 4}, x_{2} = \frac{- 12 - 8 3}{2 \cdot 4}

x = \frac{- 12 + 8 3}{2 \cdot 4} : \frac{- 3 + 2 3}{2}

x = \frac{- 12 - 8 3}{2 \cdot 4} : - \frac{3 + 2 3}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 2 3}{2}, x = - \frac{3 + 2 3}{2}

(b + 7)^{2} = 8

(1 - x) (1 - x) = 0

x, 4 x^{2} + 4 x y + y^{2} = 21

5 x^{2} - 12 x - 9 = 0

x^{2} + 2 x - 15 = 0

What are the solutions to the equation 4x^2+12x-3=0 ?
The solutions to the equation 4x^2+12x-3=0 are x=(-3+2sqrt(3))/2 ,x=-(3+2sqrt(3))/2
Find the zeros of 4x^2+12x-3=0
The zeros of 4x^2+12x-3=0 are x=(-3+2sqrt(3))/2 ,x=-(3+2sqrt(3))/2