What are the solutions to the equation 6r^2+9r+7=0 ?

The solutions to the equation 6r^2+9r+7=0 are r=-3/4+i(sqrt(87))/(12),r=-3/4-i(sqrt(87))/(12)

Find the zeros of 6r^2+9r+7=0

The zeros of 6r^2+9r+7=0 are r=-3/4+i(sqrt(87))/(12),r=-3/4-i(sqrt(87))/(12)

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6 r^{2} + 9 r + 7 = 0

r = - \frac{3}{4} + i \frac{87}{12}, r = - \frac{3}{4} - i \frac{87}{12}

Solution steps

6 r^{2} + 9 r + 7 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 6 \cdot 7}{2 \cdot 6}

Simplify

9^{2} - 4 \cdot 6 \cdot 7 : 87 i

r_{1, 2} = \frac{- 9 \pm 87 i}{2 \cdot 6}

Separate the solutions

r_{1} = \frac{- 9 + 87 i}{2 \cdot 6}, r_{2} = \frac{- 9 - 87 i}{2 \cdot 6}

r = \frac{- 9 + 87 i}{2 \cdot 6} : - \frac{3}{4} + i \frac{87}{12}

r = \frac{- 9 - 87 i}{2 \cdot 6} : - \frac{3}{4} - i \frac{87}{12}

The solutions to the quadratic equation are:

r = - \frac{3}{4} + i \frac{87}{12}, r = - \frac{3}{4} - i \frac{87}{12}

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What are the solutions to the equation 6r^2+9r+7=0 ?
The solutions to the equation 6r^2+9r+7=0 are r=-3/4+i(sqrt(87))/(12),r=-3/4-i(sqrt(87))/(12)
Find the zeros of 6r^2+9r+7=0
The zeros of 6r^2+9r+7=0 are r=-3/4+i(sqrt(87))/(12),r=-3/4-i(sqrt(87))/(12)