What are the solutions to the equation a^2-3a=0 ?

The solutions to the equation a^2-3a=0 are a=3,a=0

Find the zeros of a^2-3a=0

The zeros of a^2-3a=0 are a=3,a=0

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a^{2} - 3 a = 0

a = 3, a = 0

Solution steps

a^{2} - 3 a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

a_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, a_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

a = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

a = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

a = 3, a = 0

6 r^{2} + 9 r + 7 = 0

(x + 188) (x + 380) = 0

5 x^{2} - 120 = 5

\frac{1}{20} x^{2} + 4 x + 100 = 0

x^{2} + 20 x - 8 = 0

What are the solutions to the equation a^2-3a=0 ?
The solutions to the equation a^2-3a=0 are a=3,a=0
Find the zeros of a^2-3a=0
The zeros of a^2-3a=0 are a=3,a=0