What are the solutions to the equation quadraticformula-2x^2+8x+10=0 ?

The solutions to the equation quadraticformula-2x^2+8x+10=0 are x=-1,x=5

Find the zeros of quadraticformula-2x^2+8x+10=0

The zeros of quadraticformula-2x^2+8x+10=0 are x=-1,x=5

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- 2 x^{2} + 8 x + 10 = 0

x = - 1, x = 5

Solution steps

- 2 x^{2} + 8 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) \cdot 10}{2 ( - 2 )}

8^{2} - 4 (- 2) \cdot 10 = 12

x_{1, 2} = \frac{- 8 \pm 12}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 8 + 12}{2 ( - 2 )}, x_{2} = \frac{- 8 - 12}{2 ( - 2 )}

x = \frac{- 8 + 12}{2 ( - 2 )} : - 1

x = \frac{- 8 - 12}{2 ( - 2 )} : 5

The solutions to the quadratic equation are:

x = - 1, x = 5

2 x^{2} = - x - 10

6 x^{2} + 9 = - 55 x

7 = (x - 4)^{2} + 3

3 0^{2} + 1 6^{2} = c^{2}

2 z^{2} - 50 = 100

What are the solutions to the equation quadraticformula-2x^2+8x+10=0 ?
The solutions to the equation quadraticformula-2x^2+8x+10=0 are x=-1,x=5
Find the zeros of quadraticformula-2x^2+8x+10=0
The zeros of quadraticformula-2x^2+8x+10=0 are x=-1,x=5