What are the solutions to the equation (x+1)^2=49 ?

The solutions to the equation (x+1)^2=49 are x=6,x=-8

Find the zeros of (x+1)^2=49

The zeros of (x+1)^2=49 are x=6,x=-8

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(x + 1)^{2} = 49

x = 6, x = - 8

Solution steps

(x + 1)^{2} = 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 49 : x = 6

Solve

x + 1 = - 49 : x = - 8

The solutions to the quadratic equation are:

x = 6, x = - 8

16 x^{2} - 32 x + 16 = 1

a^{2} + 2 a - 1 = 0

x^{2} + 2 x - 7 = 17

- 3 a^{2} - 8 a - 5 = 0

x^{2} + 0 x - 4 = 0

What are the solutions to the equation (x+1)^2=49 ?
The solutions to the equation (x+1)^2=49 are x=6,x=-8
Find the zeros of (x+1)^2=49
The zeros of (x+1)^2=49 are x=6,x=-8