What are the solutions to the equation 5n^2+19n+12=0 ?

The solutions to the equation 5n^2+19n+12=0 are n=-4/5 ,n=-3

Find the zeros of 5n^2+19n+12=0

The zeros of 5n^2+19n+12=0 are n=-4/5 ,n=-3

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5 n^{2} + 19 n + 12 = 0

n = - \frac{4}{5}, n = - 3

Decimal Notation

n = - 0.8, n = - 3

Solution steps

5 n^{2} + 19 n + 12 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 5 \cdot 12}{2 \cdot 5}

1 9^{2} - 4 \cdot 5 \cdot 12 = 11

n_{1, 2} = \frac{- 19 \pm 11}{2 \cdot 5}

Separate the solutions

n_{1} = \frac{- 19 + 11}{2 \cdot 5}, n_{2} = \frac{- 19 - 11}{2 \cdot 5}

n = \frac{- 19 + 11}{2 \cdot 5} : - \frac{4}{5}

n = \frac{- 19 - 11}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

n = - \frac{4}{5}, n = - 3

19 x^{2} = 0

s^{2} - s + 1 = 0

x^{2} + 4^{2} = 6^{2}

32 x^{2} - 6 x + 9 = 0

x^{2} - 3 x - 1

What are the solutions to the equation 5n^2+19n+12=0 ?
The solutions to the equation 5n^2+19n+12=0 are n=-4/5 ,n=-3
Find the zeros of 5n^2+19n+12=0
The zeros of 5n^2+19n+12=0 are n=-4/5 ,n=-3