What are the solutions to the equation 6x^2+42x+60=0 ?

The solutions to the equation 6x^2+42x+60=0 are x=-2,x=-5

Find the zeros of 6x^2+42x+60=0

The zeros of 6x^2+42x+60=0 are x=-2,x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} + 42 x + 60 = 0

x = - 2, x = - 5

Solution steps

6 x^{2} + 42 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 42 \pm 4 2 ^{2} - 4 \cdot 6 \cdot 60}{2 \cdot 6}

4 2^{2} - 4 \cdot 6 \cdot 60 = 18

x_{1, 2} = \frac{- 42 \pm 18}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 42 + 18}{2 \cdot 6}, x_{2} = \frac{- 42 - 18}{2 \cdot 6}

x = \frac{- 42 + 18}{2 \cdot 6} : - 2

x = \frac{- 42 - 18}{2 \cdot 6} : - 5

The solutions to the quadratic equation are:

x = - 2, x = - 5

x, f = m x^{2}

(x - 4)^{2} = 45

3 x^{2} - 4 x + 1 = 0

25 x^{2} + 10 x + 25 = 0

4 s^{2} - 81 = 0

What are the solutions to the equation 6x^2+42x+60=0 ?
The solutions to the equation 6x^2+42x+60=0 are x=-2,x=-5
Find the zeros of 6x^2+42x+60=0
The zeros of 6x^2+42x+60=0 are x=-2,x=-5