What are the solutions to the equation factor 3x^2-4x+1=0 ?

The solutions to the equation factor 3x^2-4x+1=0 are x= 1/3 ,x=1

Find the zeros of factor 3x^2-4x+1=0

The zeros of factor 3x^2-4x+1=0 are x= 1/3 ,x=1

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3 x^{2} - 4 x + 1 = 0

x = \frac{1}{3}, x = 1

Decimal Notation

x = 0.33333 \dots, x = 1

Solution steps

3 x^{2} - 4 x + 1 = 0

Factor

3 x^{2} - 4 x + 1 : (3 x - 1) (x - 1)

(3 x - 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 1 = 0 or x - 1 = 0

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

x - 1 = 0 : x = 1

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = 1

25 x^{2} + 10 x + 25 = 0

4 s^{2} - 81 = 0

6 x^{2} - 48 x = 0

- 16 t^{2} + 48 t + 160 = 160

r (r + 4) = 0

What are the solutions to the equation factor 3x^2-4x+1=0 ?
The solutions to the equation factor 3x^2-4x+1=0 are x= 1/3 ,x=1
Find the zeros of factor 3x^2-4x+1=0
The zeros of factor 3x^2-4x+1=0 are x= 1/3 ,x=1