What are the solutions to the equation z^2+7z+10=0 ?

The solutions to the equation z^2+7z+10=0 are z=-2,z=-5

Find the zeros of z^2+7z+10=0

The zeros of z^2+7z+10=0 are z=-2,z=-5

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z^{2} + 7 z + 10 = 0

z = - 2, z = - 5

Solution steps

z^{2} + 7 z + 10 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 10 = 3

z_{1, 2} = \frac{- 7 \pm 3}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 7 + 3}{2 \cdot 1}, z_{2} = \frac{- 7 - 3}{2 \cdot 1}

z = \frac{- 7 + 3}{2 \cdot 1} : - 2

z = \frac{- 7 - 3}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

z = - 2, z = - 5

r^{2} - 18 = 7 r

s^{2} - 2 s + 4

\frac{2 x ^{2}}{9} - \frac{1}{50} = 0

x, x^{2} y^{1} = 4 x^{2} + 7 x y + 2 y^{2}

1 0^{2} + 4^{2} = c^{2}

What are the solutions to the equation z^2+7z+10=0 ?
The solutions to the equation z^2+7z+10=0 are z=-2,z=-5
Find the zeros of z^2+7z+10=0
The zeros of z^2+7z+10=0 are z=-2,z=-5