What are the solutions to the equation 2x^2-14x-60=0 ?

The solutions to the equation 2x^2-14x-60=0 are x=10,x=-3

Find the zeros of 2x^2-14x-60=0

The zeros of 2x^2-14x-60=0 are x=10,x=-3

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2 x^{2} - 14 x - 60 = 0

x = 10, x = - 3

Solution steps

2 x^{2} - 14 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 2 ( - 60 )}{2 \cdot 2}

(- 14)^{2} - 4 \cdot 2 (- 60) = 26

x_{1, 2} = \frac{- ( - 14 ) \pm 26}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 26}{2 \cdot 2}, x_{2} = \frac{- ( - 14 ) - 26}{2 \cdot 2}

x = \frac{- ( - 14 ) + 26}{2 \cdot 2} : 10

x = \frac{- ( - 14 ) - 26}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = 10, x = - 3

\frac{1}{2} x^{2} + 1 = 0

2^{2} + 1. 5^{2} = x^{2}

(x + 2) 2 + 3 (x + 1) (x + 4) = (x - 3) (x + 3) - 1

2 (x + 5)^{2} = 8

9 x^{2} - 16 x - 7 = 2 x + 9

What are the solutions to the equation 2x^2-14x-60=0 ?
The solutions to the equation 2x^2-14x-60=0 are x=10,x=-3
Find the zeros of 2x^2-14x-60=0
The zeros of 2x^2-14x-60=0 are x=10,x=-3