What are the solutions to the equation -2x^2+10=0 ?

The solutions to the equation -2x^2+10=0 are x=sqrt(5),x=-sqrt(5)

Find the zeros of -2x^2+10=0

The zeros of -2x^2+10=0 are x=sqrt(5),x=-sqrt(5)

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- 2 x^{2} + 10 = 0

x = 5, x = - 5

Decimal Notation

x = 2.23606 \dots, x = - 2.23606 \dots

Solution steps

- 2 x^{2} + 10 = 0

Move

10

to the right side

- 2 x^{2} = - 10

Divide both sides by

- 2

x^{2} = 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 5, x = - 5

- \frac{7}{4} x^{2} + \frac{3}{2} x = 0

(x - 5)^{2} = 2 x + 14

x^{2} + 1.2 x + 0.56 = 0.91

6 y^{2} - 19 y + 8 = 0

x = - x^{2} + 2 x + 3

What are the solutions to the equation -2x^2+10=0 ?
The solutions to the equation -2x^2+10=0 are x=sqrt(5),x=-sqrt(5)
Find the zeros of -2x^2+10=0
The zeros of -2x^2+10=0 are x=sqrt(5),x=-sqrt(5)