What are the solutions to the equation (x-5)^2=2x+14 ?

The solutions to the equation (x-5)^2=2x+14 are x=11,x=1

Find the zeros of (x-5)^2=2x+14

The zeros of (x-5)^2=2x+14 are x=11,x=1

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(x - 5)^{2} = 2 x + 14

x = 11, x = 1

Solution steps

(x - 5)^{2} = 2 x + 14

Expand

(x - 5)^{2} : x^{2} - 10 x + 25

x^{2} - 10 x + 25 = 2 x + 14

Move

14

to the left side

x^{2} - 10 x + 11 = 2 x

Move

2 x

to the left side

x^{2} - 12 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 11 = 10

x_{1, 2} = \frac{- ( - 12 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 10}{2 \cdot 1}

x = \frac{- ( - 12 ) + 10}{2 \cdot 1} : 11

x = \frac{- ( - 12 ) - 10}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 11, x = 1

x^{2} + 1.2 x + 0.56 = 0.91

6 y^{2} - 19 y + 8 = 0

x = - x^{2} + 2 x + 3

12 x^{2} + 18 x + 6 = 0

(8 x - 10) (x - 1) = 0

What are the solutions to the equation (x-5)^2=2x+14 ?
The solutions to the equation (x-5)^2=2x+14 are x=11,x=1
Find the zeros of (x-5)^2=2x+14
The zeros of (x-5)^2=2x+14 are x=11,x=1