What are the solutions to the equation solvefor x,2x^2+7x+5=0 ?

The solutions to the equation solvefor x,2x^2+7x+5=0 are x=-1,x=-5/2

Find the zeros of solvefor x,2x^2+7x+5=0

The zeros of solvefor x,2x^2+7x+5=0 are x=-1,x=-5/2

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x, 2 x^{2} + 7 x + 5 = 0

x = - 1, x = - \frac{5}{2}

Solution steps

2 x^{2} + 7 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

7^{2} - 4 \cdot 2 \cdot 5 = 3

x_{1, 2} = \frac{- 7 \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 3}{2 \cdot 2}, x_{2} = \frac{- 7 - 3}{2 \cdot 2}

x = \frac{- 7 + 3}{2 \cdot 2} : - 1

x = \frac{- 7 - 3}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{5}{2}

x (4 x - 1) = 5

u, A = 28 u^{2}

n^{2} + 8 = 80

2 x^{2} - 61 = 139

a^{2} - 64 = 0

What are the solutions to the equation solvefor x,2x^2+7x+5=0 ?
The solutions to the equation solvefor x,2x^2+7x+5=0 are x=-1,x=-5/2
Find the zeros of solvefor x,2x^2+7x+5=0
The zeros of solvefor x,2x^2+7x+5=0 are x=-1,x=-5/2