What are the solutions to the equation solvefor x,x^2-8x+16=0 ?

The solutions to the equation solvefor x,x^2-8x+16=0 are x=4

Find the zeros of solvefor x,x^2-8x+16=0

The zeros of solvefor x,x^2-8x+16=0 are x=4

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x, x^{2} - 8 x + 16 = 0

x = 4

Solution steps

x^{2} - 8 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 16 = 0

x_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 8 )}{2 \cdot 1}

\frac{- ( - 8 )}{2 \cdot 1} = 4

x = 4

The solution to the quadratic equation is:

x = 4

(x - 4)^{2} + (x - 1) \cdot (x + 1) = 25

x^{2} + 3 = - 24

- x^{2} + 5 x + 7 = 0

3 x^{2} - 5 = - 14 x

3 x^{2} + 5 x - 2 = 0

What are the solutions to the equation solvefor x,x^2-8x+16=0 ?
The solutions to the equation solvefor x,x^2-8x+16=0 are x=4
Find the zeros of solvefor x,x^2-8x+16=0
The zeros of solvefor x,x^2-8x+16=0 are x=4