What are the solutions to the equation (x-4)^2+(x-1)*(x+1)=25 ?

The solutions to the equation (x-4)^2+(x-1)*(x+1)=25 are x=5,x=-1

Find the zeros of (x-4)^2+(x-1)*(x+1)=25

The zeros of (x-4)^2+(x-1)*(x+1)=25 are x=5,x=-1

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(x - 4)^{2} + (x - 1) \cdot (x + 1) = 25

x = 5, x = - 1

Solution steps

(x - 4)^{2} + (x - 1) (x + 1) = 25

Expand

(x - 4)^{2} + (x - 1) (x + 1) : 2 x^{2} - 8 x + 15

2 x^{2} - 8 x + 15 = 25

Move

25

to the left side

2 x^{2} - 8 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 (- 10) = 12

x_{1, 2} = \frac{- ( - 8 ) \pm 12}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 12}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 12}{2 \cdot 2}

x = \frac{- ( - 8 ) + 12}{2 \cdot 2} : 5

x = \frac{- ( - 8 ) - 12}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

x^{2} + 3 = - 24

- x^{2} + 5 x + 7 = 0

3 x^{2} - 5 = - 14 x

3 x^{2} + 5 x - 2 = 0

x^{2} + 32 = - 14 x

What are the solutions to the equation (x-4)^2+(x-1)*(x+1)=25 ?
The solutions to the equation (x-4)^2+(x-1)*(x+1)=25 are x=5,x=-1
Find the zeros of (x-4)^2+(x-1)*(x+1)=25
The zeros of (x-4)^2+(x-1)*(x+1)=25 are x=5,x=-1