What are the solutions to the equation x^2+4x+85=0 ?

The solutions to the equation x^2+4x+85=0 are x=-2+9i,x=-2-9i

Find the zeros of x^2+4x+85=0

The zeros of x^2+4x+85=0 are x=-2+9i,x=-2-9i

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x^{2} + 4 x + 85 = 0

x = - 2 + 9 i, x = - 2 - 9 i

Solution steps

x^{2} + 4 x + 85 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 85}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 85 : 18 i

x_{1, 2} = \frac{- 4 \pm 18 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 18 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 18 i}{2 \cdot 1}

x = \frac{- 4 + 18 i}{2 \cdot 1} : - 2 + 9 i

x = \frac{- 4 - 18 i}{2 \cdot 1} : - 2 - 9 i

The solutions to the quadratic equation are:

x = - 2 + 9 i, x = - 2 - 9 i

x^{2} - 6 x = - x^{2} + 6 x

a, 9 a^{2} + 12 ab = 32 b^{2}

c^{2} = 15

x^{2} - \frac{2}{3} = 0

4 x^{2} + 60 x + 200 - 264 = 0

What are the solutions to the equation x^2+4x+85=0 ?
The solutions to the equation x^2+4x+85=0 are x=-2+9i,x=-2-9i
Find the zeros of x^2+4x+85=0
The zeros of x^2+4x+85=0 are x=-2+9i,x=-2-9i