What are the solutions to the equation 8x+3x^2+10=2 ?

The solutions to the equation 8x+3x^2+10=2 are x=-4/3+i(2sqrt(2))/3 ,x=-4/3-i(2sqrt(2))/3

Find the zeros of 8x+3x^2+10=2

The zeros of 8x+3x^2+10=2 are x=-4/3+i(2sqrt(2))/3 ,x=-4/3-i(2sqrt(2))/3

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8 x + 3 x^{2} + 10 = 2

x = - \frac{4}{3} + i \frac{2 2}{3}, x = - \frac{4}{3} - i \frac{2 2}{3}

Solution steps

8 x + 3 x^{2} + 10 = 2

Move

2

to the left side

3 x^{2} + 8 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

Simplify

8^{2} - 4 \cdot 3 \cdot 8 : 42 i

x_{1, 2} = \frac{- 8 \pm 4 2 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 4 2 i}{2 \cdot 3}, x_{2} = \frac{- 8 - 4 2 i}{2 \cdot 3}

x = \frac{- 8 + 4 2 i}{2 \cdot 3} : - \frac{4}{3} + i \frac{2 2}{3}

x = \frac{- 8 - 4 2 i}{2 \cdot 3} : - \frac{4}{3} - i \frac{2 2}{3}

The solutions to the quadratic equation are:

x = - \frac{4}{3} + i \frac{2 2}{3}, x = - \frac{4}{3} - i \frac{2 2}{3}

v^{2} - 4 v + 26 = 4

12 x = x^{2}

- 6 x^{2} + 7 x + 3 = 0

(k - 2) x^{2} - (2 k - 1) x + (k - 1) = 0

3 x^{2} - 12 x + 24 = 0

What are the solutions to the equation 8x+3x^2+10=2 ?
The solutions to the equation 8x+3x^2+10=2 are x=-4/3+i(2sqrt(2))/3 ,x=-4/3-i(2sqrt(2))/3
Find the zeros of 8x+3x^2+10=2
The zeros of 8x+3x^2+10=2 are x=-4/3+i(2sqrt(2))/3 ,x=-4/3-i(2sqrt(2))/3