What are the solutions to the equation 10-3x=x^2-6x ?

The solutions to the equation 10-3x=x^2-6x are x=5,x=-2

Find the zeros of 10-3x=x^2-6x

The zeros of 10-3x=x^2-6x are x=5,x=-2

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10 - 3 x = x^{2} - 6 x

x = 5, x = - 2

Solution steps

10 - 3 x = x^{2} - 6 x

Switch sides

x^{2} - 6 x = 10 - 3 x

Move

3 x

to the left side

x^{2} - 3 x = 10

Move

10

to the left side

x^{2} - 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 10) = 7

x_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 1}

x = \frac{- ( - 3 ) + 7}{2 \cdot 1} : 5

x = \frac{- ( - 3 ) - 7}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 5, x = - 2

13 n^{2} - 7 = - 6 - 3 n^{2}

y^{2} - 24 = 0

3 x^{2} - 186 x + 450 = 90

9 x^{2} - 14 x - 8 = 0

6 n^{2} + 9 n + 1 = 0

What are the solutions to the equation 10-3x=x^2-6x ?
The solutions to the equation 10-3x=x^2-6x are x=5,x=-2
Find the zeros of 10-3x=x^2-6x
The zeros of 10-3x=x^2-6x are x=5,x=-2