What are the solutions to the equation x^2+25=12x ?

The solutions to the equation x^2+25=12x are x=6+sqrt(11),x=6-sqrt(11)

Find the zeros of x^2+25=12x

The zeros of x^2+25=12x are x=6+sqrt(11),x=6-sqrt(11)

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x^{2} + 25 = 12 x

x = 6 + 11, x = 6 - 11

Solution steps

x^{2} + 25 = 12 x

Move

12 x

to the left side

x^{2} + 25 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 12 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 25 = 211

x_{1, 2} = \frac{- ( - 12 ) \pm 2 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 11}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 11}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 11}{2 \cdot 1} : 6 + 11

x = \frac{- ( - 12 ) - 2 11}{2 \cdot 1} : 6 - 11

The solutions to the quadratic equation are:

x = 6 + 11, x = 6 - 11

x^{2} - 18 x + 52 = 8

s^{2} - 10 s + 21 = 0

15 a^{2} + a = 2

C = - 5 t^{2} + 750

- 12 x^{2} + 4 x = 0

What are the solutions to the equation x^2+25=12x ?
The solutions to the equation x^2+25=12x are x=6+sqrt(11),x=6-sqrt(11)
Find the zeros of x^2+25=12x
The zeros of x^2+25=12x are x=6+sqrt(11),x=6-sqrt(11)