What are the solutions to the equation 2k(k-5)=0 ?

The solutions to the equation 2k(k-5)=0 are k=0,k=5

Find the zeros of 2k(k-5)=0

The zeros of 2k(k-5)=0 are k=0,k=5

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2 k (k - 5) = 0

k = 0, k = 5

Solution steps

2 k (k - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

k = 0 or k - 5 = 0

Solve

k - 5 = 0 : k = 5

The solutions to the quadratic equation are:

k = 0, k = 5

- 3 x^{2} + 4 = 0

- x^{2} - 6 x + 7 = 0

7 x^{2} - 3 x + 5 = 0

8 x^{2} - 17 x + 2 = 0

(x - 1) (x + 7) = 0

What are the solutions to the equation 2k(k-5)=0 ?
The solutions to the equation 2k(k-5)=0 are k=0,k=5
Find the zeros of 2k(k-5)=0
The zeros of 2k(k-5)=0 are k=0,k=5