What are the solutions to the equation -3x^2+4=0 ?

The solutions to the equation -3x^2+4=0 are x= 2/(sqrt(3)),x=-2/(sqrt(3))

Find the zeros of -3x^2+4=0

The zeros of -3x^2+4=0 are x= 2/(sqrt(3)),x=-2/(sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 x^{2} + 4 = 0

x = \frac{2}{3}, x = - \frac{2}{3}

Solution steps

- 3 x^{2} + 4 = 0

Move

4

to the right side

- 3 x^{2} = - 4

Divide both sides by

- 3

x^{2} = \frac{4}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{4}{3}, x = - \frac{4}{3}

\frac{4}{3} = \frac{2}{3}

- \frac{4}{3} = - \frac{2}{3}

x = \frac{2}{3}, x = - \frac{2}{3}

- x^{2} - 6 x + 7 = 0

7 x^{2} - 3 x + 5 = 0

8 x^{2} - 17 x + 2 = 0

(x - 1) (x + 7) = 0

- 2 x^{2} + 20 x - 24 = 0

What are the solutions to the equation -3x^2+4=0 ?
The solutions to the equation -3x^2+4=0 are x= 2/(sqrt(3)),x=-2/(sqrt(3))
Find the zeros of -3x^2+4=0
The zeros of -3x^2+4=0 are x= 2/(sqrt(3)),x=-2/(sqrt(3))