What are the solutions to the equation -x^2(2)-4+4(2)-2x=0 ?

The solutions to the equation -x^2(2)-4+4(2)-2x=0 are x=-2,x=1

Find the zeros of -x^2(2)-4+4(2)-2x=0

The zeros of -x^2(2)-4+4(2)-2x=0 are x=-2,x=1

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- x^{2} (2) - 4 + 4 (2) - 2 x = 0

x = - 2, x = 1

Solution steps

- x^{2} (2) - 4 + 4 (2) - 2 x = 0

Expand

- x^{2} (2) - 4 + 4 (2) - 2 x : - 2 x^{2} - 2 x + 4

- 2 x^{2} - 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 2 ) \cdot 4}{2 ( - 2 )}

(- 2)^{2} - 4 (- 2) \cdot 4 = 6

x_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6}{2 ( - 2 )}, x_{2} = \frac{- ( - 2 ) - 6}{2 ( - 2 )}

x = \frac{- ( - 2 ) + 6}{2 ( - 2 )} : - 2

x = \frac{- ( - 2 ) - 6}{2 ( - 2 )} : 1

The solutions to the quadratic equation are:

x = - 2, x = 1

r^{2} + 49 r = 0

- 3 x^{2} + 7 = 0

6 x^{2} + 7 x = 3

x^{2} = 16

3 p^{2} - 5 p + 2 = 0

What are the solutions to the equation -x^2(2)-4+4(2)-2x=0 ?
The solutions to the equation -x^2(2)-4+4(2)-2x=0 are x=-2,x=1
Find the zeros of -x^2(2)-4+4(2)-2x=0
The zeros of -x^2(2)-4+4(2)-2x=0 are x=-2,x=1