What are the solutions to the equation -3x^2+7=0 ?

The solutions to the equation -3x^2+7=0 are x=sqrt(7/3),x=-sqrt(7/3)

Find the zeros of -3x^2+7=0

The zeros of -3x^2+7=0 are x=sqrt(7/3),x=-sqrt(7/3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 x^{2} + 7 = 0

x = \frac{7}{3}, x = - \frac{7}{3}

Solution steps

- 3 x^{2} + 7 = 0

Move

7

to the right side

- 3 x^{2} = - 7

Divide both sides by

- 3

x^{2} = \frac{7}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{7}{3}, x = - \frac{7}{3}

6 x^{2} + 7 x = 3

x^{2} = 16

3 p^{2} - 5 p + 2 = 0

y^{2} - 10 y + 21 = 0

x = x^{2} + 2 x - 8

What are the solutions to the equation -3x^2+7=0 ?
The solutions to the equation -3x^2+7=0 are x=sqrt(7/3),x=-sqrt(7/3)
Find the zeros of -3x^2+7=0
The zeros of -3x^2+7=0 are x=sqrt(7/3),x=-sqrt(7/3)