What are the solutions to the equation 9x^2+18x=0 ?

The solutions to the equation 9x^2+18x=0 are x=0,x=-2

Find the zeros of 9x^2+18x=0

The zeros of 9x^2+18x=0 are x=0,x=-2

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9 x^{2} + 18 x = 0

x = 0, x = - 2

Solution steps

9 x^{2} + 18 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 9 \cdot 0}{2 \cdot 9}

1 8^{2} - 4 \cdot 9 \cdot 0 = 18

x_{1, 2} = \frac{- 18 \pm 18}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 18 + 18}{2 \cdot 9}, x_{2} = \frac{- 18 - 18}{2 \cdot 9}

x = \frac{- 18 + 18}{2 \cdot 9} : 0

x = \frac{- 18 - 18}{2 \cdot 9} : - 2

The solutions to the quadratic equation are:

x = 0, x = - 2

x^{2} + 16 = 81

- 3 x^{2} + 2 x - 5 = 0

5 X^{2} - 500 = 0

3 x^{2} + 32 x = 11

\frac{1}{2} x^{2} + x + 4 = 0

What are the solutions to the equation 9x^2+18x=0 ?
The solutions to the equation 9x^2+18x=0 are x=0,x=-2
Find the zeros of 9x^2+18x=0
The zeros of 9x^2+18x=0 are x=0,x=-2