What are the solutions to the equation 3x^2=x^2+25 ?

The solutions to the equation 3x^2=x^2+25 are x= 5/(sqrt(2)),x=-5/(sqrt(2))

Find the zeros of 3x^2=x^2+25

The zeros of 3x^2=x^2+25 are x= 5/(sqrt(2)),x=-5/(sqrt(2))

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3 x^{2} = x^{2} + 25

x = \frac{5}{2}, x = - \frac{5}{2}

Decimal Notation

x = 3.53553 \dots, x = - 3.53553 \dots

Solution steps

3 x^{2} = x^{2} + 25

Move

x^{2}

to the left side

2 x^{2} = 25

Divide both sides by

2

x^{2} = \frac{25}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{2}, x = - \frac{25}{2}

\frac{25}{2} = \frac{5}{2}

- \frac{25}{2} = - \frac{5}{2}

x = \frac{5}{2}, x = - \frac{5}{2}

24 x - 12 x^{2} = 0

- 2 x^{2} + 3 = 11

x^{2} - 16 x - 55 = 0

x^{2} + 21 x + 104 = 0

x^{2} - 10 + 21 = 0

What are the solutions to the equation 3x^2=x^2+25 ?
The solutions to the equation 3x^2=x^2+25 are x= 5/(sqrt(2)),x=-5/(sqrt(2))
Find the zeros of 3x^2=x^2+25
The zeros of 3x^2=x^2+25 are x= 5/(sqrt(2)),x=-5/(sqrt(2))