What are the solutions to the equation -2x^2+3=11 ?

The solutions to the equation -2x^2+3=11 are x=2i,x=-2i

Find the zeros of -2x^2+3=11

The zeros of -2x^2+3=11 are x=2i,x=-2i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} + 3 = 11

x = 2 i, x = - 2 i

Solution steps

- 2 x^{2} + 3 = 11

Move

3

to the right side

- 2 x^{2} = 8

Divide both sides by

- 2

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

x^{2} - 16 x - 55 = 0

x^{2} + 21 x + 104 = 0

x^{2} - 10 + 21 = 0

x^{2} - 4 x + 49 = 0

x^{(2)} + x^{(2)} + 2 x + 1 = x^{(2)} + 4 x + 4 + 60

What are the solutions to the equation -2x^2+3=11 ?
The solutions to the equation -2x^2+3=11 are x=2i,x=-2i
Find the zeros of -2x^2+3=11
The zeros of -2x^2+3=11 are x=2i,x=-2i