What are the solutions to the equation 0=-3x^2+30x+600 ?

The solutions to the equation 0=-3x^2+30x+600 are x=-10,x=20

Find the zeros of 0=-3x^2+30x+600

The zeros of 0=-3x^2+30x+600 are x=-10,x=20

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0 = - 3 x^{2} + 30 x + 600

x = - 10, x = 20

Solution steps

0 = - 3 x^{2} + 30 x + 600

Switch sides

- 3 x^{2} + 30 x + 600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 ( - 3 ) \cdot 600}{2 ( - 3 )}

3 0^{2} - 4 (- 3) \cdot 600 = 90

x_{1, 2} = \frac{- 30 \pm 90}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 30 + 90}{2 ( - 3 )}, x_{2} = \frac{- 30 - 90}{2 ( - 3 )}

x = \frac{- 30 + 90}{2 ( - 3 )} : - 10

x = \frac{- 30 - 90}{2 ( - 3 )} : 20

The solutions to the quadratic equation are:

x = - 10, x = 20

b (b + 12) = 0

3 y^{2} + 8 y - 6 = 0

x^{2} + 3 x - 10

x^{2} - 5 x = - 9

x, x^{2} + y^{2} + 5 z^{2} + 2 x z + 4 yz - 4 = 0

What are the solutions to the equation 0=-3x^2+30x+600 ?
The solutions to the equation 0=-3x^2+30x+600 are x=-10,x=20
Find the zeros of 0=-3x^2+30x+600
The zeros of 0=-3x^2+30x+600 are x=-10,x=20