What are the solutions to the equation 4-x^2=4-x ?

The solutions to the equation 4-x^2=4-x are x=0,x=1

Find the zeros of 4-x^2=4-x

The zeros of 4-x^2=4-x are x=0,x=1

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4 - x^{2} = 4 - x

x = 0, x = 1

Solution steps

4 - x^{2} = 4 - x

Move

x

to the left side

4 - x^{2} + x = 4

Move

4

to the left side

- x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 ( - 1 )}, x_{2} = \frac{- 1 - 1}{2 ( - 1 )}

x = \frac{- 1 + 1}{2 ( - 1 )} : 0

x = \frac{- 1 - 1}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = 0, x = 1

(x - 8)^{2} = - 16 x

m, f = (15 m \cdot 30 m) + 20 m^{2}

8 x - 65 + x^{2} = 0

0 = - 3 x^{2} + 30 x + 600

b (b + 12) = 0

What are the solutions to the equation 4-x^2=4-x ?
The solutions to the equation 4-x^2=4-x are x=0,x=1
Find the zeros of 4-x^2=4-x
The zeros of 4-x^2=4-x are x=0,x=1