What are the solutions to the equation b(b+12)=0 ?

The solutions to the equation b(b+12)=0 are b=0,b=-12

Find the zeros of b(b+12)=0

The zeros of b(b+12)=0 are b=0,b=-12

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b (b + 12) = 0

b = 0, b = - 12

Solution steps

b (b + 12) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

b = 0 or b + 12 = 0

Solve

b + 12 = 0 : b = - 12

The solutions to the quadratic equation are:

b = 0, b = - 12

3 y^{2} + 8 y - 6 = 0

x^{2} + 3 x - 10

x^{2} - 5 x = - 9

x, x^{2} + y^{2} + 5 z^{2} + 2 x z + 4 yz - 4 = 0

\frac{x ^{2}}{10} - 4 = 12

What are the solutions to the equation b(b+12)=0 ?
The solutions to the equation b(b+12)=0 are b=0,b=-12
Find the zeros of b(b+12)=0
The zeros of b(b+12)=0 are b=0,b=-12