What are the solutions to the equation 3x^2-46x+120=0 ?

The solutions to the equation 3x^2-46x+120=0 are x=12,x= 10/3

Find the zeros of 3x^2-46x+120=0

The zeros of 3x^2-46x+120=0 are x=12,x= 10/3

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3 x^{2} - 46 x + 120 = 0

x = 12, x = \frac{10}{3}

Solution steps

3 x^{2} - 46 x + 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 46 ) \pm ( - 46 ) ^{2} - 4 \cdot 3 \cdot 120}{2 \cdot 3}

(- 46)^{2} - 4 \cdot 3 \cdot 120 = 26

x_{1, 2} = \frac{- ( - 46 ) \pm 26}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 46 ) + 26}{2 \cdot 3}, x_{2} = \frac{- ( - 46 ) - 26}{2 \cdot 3}

x = \frac{- ( - 46 ) + 26}{2 \cdot 3} : 12

x = \frac{- ( - 46 ) - 26}{2 \cdot 3} : \frac{10}{3}

The solutions to the quadratic equation are:

x = 12, x = \frac{10}{3}

20 x^{2} + 5 x = 0

0 = 3 x^{2} + 2 x - 5

0 = 3 x^{2} + 2 x + 4

b^{2} - 7 b - 18 = 0

n^{2} + 5 n - 24 = 0

What are the solutions to the equation 3x^2-46x+120=0 ?
The solutions to the equation 3x^2-46x+120=0 are x=12,x= 10/3
Find the zeros of 3x^2-46x+120=0
The zeros of 3x^2-46x+120=0 are x=12,x= 10/3