What are the solutions to the equation 0=3x^2-24x-27 ?

The solutions to the equation 0=3x^2-24x-27 are x=9,x=-1

Find the zeros of 0=3x^2-24x-27

The zeros of 0=3x^2-24x-27 are x=9,x=-1

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0 = 3 x^{2} - 24 x - 27

x = 9, x = - 1

Solution steps

0 = 3 x^{2} - 24 x - 27

Switch sides

3 x^{2} - 24 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 3 ( - 27 )}{2 \cdot 3}

(- 24)^{2} - 4 \cdot 3 (- 27) = 30

x_{1, 2} = \frac{- ( - 24 ) \pm 30}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 30}{2 \cdot 3}, x_{2} = \frac{- ( - 24 ) - 30}{2 \cdot 3}

x = \frac{- ( - 24 ) + 30}{2 \cdot 3} : 9

x = \frac{- ( - 24 ) - 30}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = 9, x = - 1

3 d^{2} + 24 d + 45 = 0

x^{2} + (17 - x)^{2} = 169

y^{2} - y - 5 = 0

(3 x + 2) (2 x - 1) = 13

2 x^{2} + 11 x - 12 = 0

What are the solutions to the equation 0=3x^2-24x-27 ?
The solutions to the equation 0=3x^2-24x-27 are x=9,x=-1
Find the zeros of 0=3x^2-24x-27
The zeros of 0=3x^2-24x-27 are x=9,x=-1