What are the solutions to the equation 4q^2+4q+1=0 ?

The solutions to the equation 4q^2+4q+1=0 are q=-1/2

Find the zeros of 4q^2+4q+1=0

The zeros of 4q^2+4q+1=0 are q=-1/2

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4 q^{2} + 4 q + 1 = 0

q = - \frac{1}{2}

Solution steps

4 q^{2} + 4 q + 1 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

q_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

q = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

q = - \frac{1}{2}

The solution to the quadratic equation is:

q = - \frac{1}{2}

x^{2} - 10 x + 25 = 0

x, 9 x^{2} - 18 x y + 9 y^{2} - x - y = 0

12 x^{2} - 88 x + 96 = 0

2 (x + 3)^{2} - 5 = 14 x + 17

10 x^{2} + 8 x = 0

What are the solutions to the equation 4q^2+4q+1=0 ?
The solutions to the equation 4q^2+4q+1=0 are q=-1/2
Find the zeros of 4q^2+4q+1=0
The zeros of 4q^2+4q+1=0 are q=-1/2