What are the solutions to the equation quadraticformula x^2-10x+25=0 ?

The solutions to the equation quadraticformula x^2-10x+25=0 are x=5

Find the zeros of quadraticformula x^2-10x+25=0

The zeros of quadraticformula x^2-10x+25=0 are x=5

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x^{2} - 10 x + 25 = 0

x = 5

Solution steps

x^{2} - 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 10 )}{2 \cdot 1}

\frac{- ( - 10 )}{2 \cdot 1} = 5

x = 5

The solution to the quadratic equation is:

x = 5

x, 9 x^{2} - 18 x y + 9 y^{2} - x - y = 0

12 x^{2} - 88 x + 96 = 0

2 (x + 3)^{2} - 5 = 14 x + 17

10 x^{2} + 8 x = 0

(x + 4)^{2} - 2 = 7

What are the solutions to the equation quadraticformula x^2-10x+25=0 ?
The solutions to the equation quadraticformula x^2-10x+25=0 are x=5
Find the zeros of quadraticformula x^2-10x+25=0
The zeros of quadraticformula x^2-10x+25=0 are x=5