What are the solutions to the equation 12x^2-88x+96=0 ?

The solutions to the equation 12x^2-88x+96=0 are x=6,x= 4/3

Find the zeros of 12x^2-88x+96=0

The zeros of 12x^2-88x+96=0 are x=6,x= 4/3

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12 x^{2} - 88 x + 96 = 0

x = 6, x = \frac{4}{3}

Solution steps

12 x^{2} - 88 x + 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 88 ) \pm ( - 88 ) ^{2} - 4 \cdot 12 \cdot 96}{2 \cdot 12}

(- 88)^{2} - 4 \cdot 12 \cdot 96 = 56

x_{1, 2} = \frac{- ( - 88 ) \pm 56}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 88 ) + 56}{2 \cdot 12}, x_{2} = \frac{- ( - 88 ) - 56}{2 \cdot 12}

x = \frac{- ( - 88 ) + 56}{2 \cdot 12} : 6

x = \frac{- ( - 88 ) - 56}{2 \cdot 12} : \frac{4}{3}

The solutions to the quadratic equation are:

x = 6, x = \frac{4}{3}

2 (x + 3)^{2} - 5 = 14 x + 17

10 x^{2} + 8 x = 0

(x + 4)^{2} - 2 = 7

2 y (5 y + 6) = 7 y

25 (x + 2)^{2} = (x - 7)^{2} - 81

What are the solutions to the equation 12x^2-88x+96=0 ?
The solutions to the equation 12x^2-88x+96=0 are x=6,x= 4/3
Find the zeros of 12x^2-88x+96=0
The zeros of 12x^2-88x+96=0 are x=6,x= 4/3