What are the solutions to the equation (x+4)^2-2=7 ?

The solutions to the equation (x+4)^2-2=7 are x=-1,x=-7

Find the zeros of (x+4)^2-2=7

The zeros of (x+4)^2-2=7 are x=-1,x=-7

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(x + 4)^{2} - 2 = 7

x = - 1, x = - 7

Solution steps

(x + 4)^{2} - 2 = 7

Move

2

to the right side

(x + 4)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 9 : x = - 1

Solve

x + 4 = - 9 : x = - 7

The solutions to the quadratic equation are:

x = - 1, x = - 7

2 y (5 y + 6) = 7 y

25 (x + 2)^{2} = (x - 7)^{2} - 81

k^{2} - 4 k + 1 = - 19

(3 - x)^{2} - (3 + x) - 2 = 0

(2 x + 3)^{2} = (x + 4) (x + 3)

What are the solutions to the equation (x+4)^2-2=7 ?
The solutions to the equation (x+4)^2-2=7 are x=-1,x=-7
Find the zeros of (x+4)^2-2=7
The zeros of (x+4)^2-2=7 are x=-1,x=-7