What are the solutions to the equation 2y(5y+6)=7y ?

The solutions to the equation 2y(5y+6)=7y are y=0,y=-1/2

Find the zeros of 2y(5y+6)=7y

The zeros of 2y(5y+6)=7y are y=0,y=-1/2

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2 y (5 y + 6) = 7 y

y = 0, y = - \frac{1}{2}

Solution steps

2 y (5 y + 6) = 7 y

Move

7 y

to the left side

2 y (5 y + 6) - 7 y = 0

Factor

2 y (5 y + 6) - 7 y : 5 y (2 y + 1)

5 y (2 y + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 2 y + 1 = 0

Solve

2 y + 1 = 0 : y = - \frac{1}{2}

The solutions to the quadratic equation are:

y = 0, y = - \frac{1}{2}

25 (x + 2)^{2} = (x - 7)^{2} - 81

k^{2} - 4 k + 1 = - 19

(3 - x)^{2} - (3 + x) - 2 = 0

(2 x + 3)^{2} = (x + 4) (x + 3)

9 x - 8 = x^{2}

What are the solutions to the equation 2y(5y+6)=7y ?
The solutions to the equation 2y(5y+6)=7y are y=0,y=-1/2
Find the zeros of 2y(5y+6)=7y
The zeros of 2y(5y+6)=7y are y=0,y=-1/2