What are the solutions to the equation (3-x)^2-(3+x)-2=0 ?

The solutions to the equation (3-x)^2-(3+x)-2=0 are x=(7+sqrt(33))/2 ,x=(7-sqrt(33))/2

Find the zeros of (3-x)^2-(3+x)-2=0

The zeros of (3-x)^2-(3+x)-2=0 are x=(7+sqrt(33))/2 ,x=(7-sqrt(33))/2

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(3 - x)^{2} - (3 + x) - 2 = 0

x = \frac{7 + 33}{2}, x = \frac{7 - 33}{2}

Solution steps

(3 - x)^{2} - (3 + x) - 2 = 0

Expand

(3 - x)^{2} - (3 + x) - 2 : x^{2} - 7 x + 4

x^{2} - 7 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 4 = 33

x_{1, 2} = \frac{- ( - 7 ) \pm 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 33}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 33}{2 \cdot 1}

x = \frac{- ( - 7 ) + 33}{2 \cdot 1} : \frac{7 + 33}{2}

x = \frac{- ( - 7 ) - 33}{2 \cdot 1} : \frac{7 - 33}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 33}{2}, x = \frac{7 - 33}{2}

(2 x + 3)^{2} = (x + 4) (x + 3)

9 x - 8 = x^{2}

x, y^{3} + 3 y^{2} - 9 y = x^{2} + 10 x + 12

x^{2} - 23 x + 44 = - 5 x + 5

2 x^{2} = - 200

What are the solutions to the equation (3-x)^2-(3+x)-2=0 ?
The solutions to the equation (3-x)^2-(3+x)-2=0 are x=(7+sqrt(33))/2 ,x=(7-sqrt(33))/2
Find the zeros of (3-x)^2-(3+x)-2=0
The zeros of (3-x)^2-(3+x)-2=0 are x=(7+sqrt(33))/2 ,x=(7-sqrt(33))/2