What are the solutions to the equation -2x^2+3x+9=0 ?

The solutions to the equation -2x^2+3x+9=0 are x=-3/2 ,x=3

Find the zeros of -2x^2+3x+9=0

The zeros of -2x^2+3x+9=0 are x=-3/2 ,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} + 3 x + 9 = 0

x = - \frac{3}{2}, x = 3

Solution steps

- 2 x^{2} + 3 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 2 ) \cdot 9}{2 ( - 2 )}

3^{2} - 4 (- 2) \cdot 9 = 9

x_{1, 2} = \frac{- 3 \pm 9}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 3 + 9}{2 ( - 2 )}, x_{2} = \frac{- 3 - 9}{2 ( - 2 )}

x = \frac{- 3 + 9}{2 ( - 2 )} : - \frac{3}{2}

x = \frac{- 3 - 9}{2 ( - 2 )} : 3

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = 3

x^{2} - 30 x + 56 = 0

x^{2} + \frac{3}{6} x + \frac{4}{6} = 0

S, A = 5 \cdot M \cdot N \cdot S^{2}

y^{2} - y = 2

0 = 12 x^{2} - 168 x + 405

What are the solutions to the equation -2x^2+3x+9=0 ?
The solutions to the equation -2x^2+3x+9=0 are x=-3/2 ,x=3
Find the zeros of -2x^2+3x+9=0
The zeros of -2x^2+3x+9=0 are x=-3/2 ,x=3