What are the solutions to the equation x^2-30x+56=0 ?

The solutions to the equation x^2-30x+56=0 are x=28,x=2

Find the zeros of x^2-30x+56=0

The zeros of x^2-30x+56=0 are x=28,x=2

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x^{2} - 30 x + 56 = 0

x = 28, x = 2

Solution steps

x^{2} - 30 x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

(- 30)^{2} - 4 \cdot 1 \cdot 56 = 26

x_{1, 2} = \frac{- ( - 30 ) \pm 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 30 ) + 26}{2 \cdot 1}, x_{2} = \frac{- ( - 30 ) - 26}{2 \cdot 1}

x = \frac{- ( - 30 ) + 26}{2 \cdot 1} : 28

x = \frac{- ( - 30 ) - 26}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 28, x = 2

x^{2} + \frac{3}{6} x + \frac{4}{6} = 0

S, A = 5 \cdot M \cdot N \cdot S^{2}

y^{2} - y = 2

0 = 12 x^{2} - 168 x + 405

x^{2} + a x = 0

What are the solutions to the equation x^2-30x+56=0 ?
The solutions to the equation x^2-30x+56=0 are x=28,x=2
Find the zeros of x^2-30x+56=0
The zeros of x^2-30x+56=0 are x=28,x=2