What are the solutions to the equation y^2-y=2 ?

The solutions to the equation y^2-y=2 are y=2,y=-1

Find the zeros of y^2-y=2

The zeros of y^2-y=2 are y=2,y=-1

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y^{2} - y = 2

y = 2, y = - 1

Solution steps

y^{2} - y = 2

Move

2

to the left side

y^{2} - y - 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 2) = 3

y_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 1}, y_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 1}

y = \frac{- ( - 1 ) + 3}{2 \cdot 1} : 2

y = \frac{- ( - 1 ) - 3}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

y = 2, y = - 1

0 = 12 x^{2} - 168 x + 405

x^{2} + a x = 0

x^{2} + x + 13 = 0

s^{2} + 6 s + 10

- 0.004 x^{2} + 250 = 0.0024 x^{2} + 0.04 x + 100

What are the solutions to the equation y^2-y=2 ?
The solutions to the equation y^2-y=2 are y=2,y=-1
Find the zeros of y^2-y=2
The zeros of y^2-y=2 are y=2,y=-1